Basic Applied Statistics 200
Solutions to Midterm 1 Spring 2002
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- (i) Method 1 because the values tend to be lower
- (ii) Method 2 because the stemplot has more spread
- (i) Method 1 looks perfectly symmetric
- (iv) neither has values far from the rest
- (ii) mean and standard deviation because it is symmetric
- 13, 19 (3rd value), 24, 28 (8th value), 31
- (i) Method 1 (ranges from 11 to 27, not 13 to 31)
-
- 0 is the mean of a standard normal distribution
- 1 is the standard deviation of standard normal z
- .1003 are GREATER (.8997 would be less)
- practically no observations are this high
- .9772-.8413=.1359
- look up .0404; the closest z is -1.75
- look up .9900 (because you want the HIGHEST 1%); the closest z is 2.33
-
- 95% are within 2 s.d.s of the mean: 5.3 plus or minus 2(.2) goes
from 4.9 to 5.7
- z=(4.8-5.3)/.2=-2.5; the proportion below is .0062
- no, not likely because the probability .0062 is so small
- for .25 below, z=-.67, so x=5.3-.67(.2)=5.166
-
- men who died (3160/2223) have the highest proportion
- 332/706=.47
- 332/1692=.20
- 374/531=.704
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- tip
- (i) increase (points slope up)
- (iii) rather strong (points are fairly tightly clustered)
- (v) +.83 because the relationship is fairly strong, but you
could take the square root of R-Sq=.686 to be sure
- (ii) same; r is independent of assignment of explanatory/response
- -.35+.15(63.30)=9.19
- 12-9.19=2.81
- (iii) it predicts 15% of the bill minus 35 cents (see regression
equation)
- (i) random scatter is a good thing in the residual plot
- (ii) decrease because it would make the clustering looser
-
- (iii) not enough replication; 5 each are small groups
- (i) no comparison is made
- (ii) no randomization; people chose what medication to take
-
- 25 is the number actually examined
- observational study; the pediatrician does not manipulate any
variables, she only observes
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